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Like if x-20 is the equation, poly(2) is enough to find the polynomial matrix. The poly function takes arguments as roots of a polynomial. The x 3 term is absent and thus has a coefficient of 0. After 3 days i have found the answer myself. If that were to occur, then about the best you can do is generate a bunch of points and do a numeric polynomial fit. Create a vector to represent the polynomial integrand 3 x 4 - 4 x 2 + 1 0 x - 2 5. But if the function handle contains comparisons of the input to values then unless the function was very carefully written, the comparisons of the symbolic variable would fail. Why might the MATLAB command real be important in this step? How does MATLAB represent the expansion of repeated poles? Verify using a plot that your calculation of h(t) indeed matches the output of MATLAB's impulse command. I - 1 3 ( 3 x 4 - 4 x 2 + 1 0 x - 2 5) d x. You should observe the need to recombine a pair of complex-conjugate linear factors into their equivalent quadratic factor. (a) Use MATLAB to generate the continuous-time transfer function 5(s + 15)(s +26)(s+ 72) s(s +56)2 (s2 +5s +30) H(s) = displaying the result in two forms: as (i) the given ratio of factors and (ii) a ratio of two polynomials (b) Use MATLAB to calculate the partial fraction expansion of H(s) in part (a), obtaining a form suitable for table look-up to determine the impulse response h(t). Transcribed image text: Exercise 1 (Transfer Function Analysis) MATLAB provides numerous commands for working with polynomials, ratios of polynomials, partial fraction expansions and transfer functions: see, for example, the commands roots, poly, conv, residue, zpk and tf.